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Write a query to display the entire details of the building whose building_type_id is 2, sorted by owner_name in ascending order.Note:1. Display all the columns present in the building table.2. Specify the condition and retrieve the correct rows in the result(condition need to be specified on building_type_id column).3. You can compare your executed result with the sample output given below.4. Order by is mandatorySample output:

Question

Write a query to display the entire details of the building whose building_type_id is 2, sorted by owner_name in ascending order.Note:1. Display all the columns present in the building table.2. Specify the condition and retrieve the correct rows in the result(condition need to be specified on building_type_id column).3. You can compare your executed result with the sample output given below.4. Order by is mandatorySample output:

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Solution

The SQL query you're looking for would look something like this:

SELECT *
FROM building
WHERE building_type_id = 2
ORDER BY owner_name ASC;

Here's what this query does, step by step:

  1. SELECT * - This part of the query selects all columns from the table. The asterisk (*) is a wildcard character that stands for "all".

  2. FROM building - This part of the query specifies the table that we're selecting data from, which in this case is the "building" table.

  3. WHERE building_type_id = 2 - This is the condition that the rows must meet in order to be included in the result set. In this case, we're only interested in rows where the "building_type_id" is 2.

  4. ORDER BY owner_name ASC - This part of the query sorts the result set by the "owner_name" column in ascending order. If you wanted to sort in descending order, you could use DESC instead of ASC.

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