The third quadrant is where both x and y are negative.

Given that the distance from the origin to the point (x, y) is 5 units, we can use the distance formula, which in this case simplifies to the equation of a circle centered at the origin:

x² + y² = r²

where r is the radius, or distance from the origin, which is 5 units. So:

x² + y² = 5²

x² + y² = 25

In the third quadrant, both x and y are negative. So we are looking for pairs of (x, y) that satisfy the equation and where x and y are both negative.

However, the question is asking for the number of such points. This is actually infinite, because there are infinitely many pairs of (x, y) that can satisfy the equation x² + y² = 25 where x and y are both negative.

For example, (-3, -4), (-4, -3), and (-5, 0) are just a few of the infinite number of points that are 5 units away from the origin in the third quadrant.

Question

The third quadrant is where both x and y are negative.

Given that the distance from the origin to the point (x, y) is 5 units, we can use the distance formula, which in this case simplifies to the equation of a circle centered at the origin:

x² + y² = r²

where r is the radius, or distance from the origin, which is 5 units. So:

x² + y² = 5²

x² + y² = 25

In the third quadrant, both x and y are negative. So we are looking for pairs of (x, y) that satisfy the equation and where x and y are both negative.

However, the question is asking for the number of such points. This is actually infinite, because there are infinitely many pairs of (x, y) that can satisfy the equation x² + y² = 25 where x and y are both negative.

For example, (-3, -4), (-4, -3), and (-5, 0) are just a few of the infinite number of points that are 5 units away from the origin in the third quadrant.

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The third quadrant is where both x and y are negative.

Given that the distance from the origin to the point (x, y) is 5 units, we can use the distance formula, which in this case simplifies to the equation of a circle centered at the origin:

x² + y² = r²

where r is the radius, or distance from the origin, which is 5 units. So:

x² + y² = 5²

x² + y² = 25

In the third quadrant, both x and y are negative. So we are looking for pairs of (x, y) that satisfy the equation and where x and y are both negative.

However, the question is asking for the number of such points. This is actually infinite, because there are infinitely many pairs of (x, y) that can satisfy the equation x² + y² = 25 where x and y are both negative.

For example, (-3, -4), (-4, -3), and (-5, 0) are just a few of the infinite number of points that are 5 units away from the origin in the third quadrant.

A point (x,y) is at a distance of 5 units from the origin. How many such points lie in the thirdquadrant?

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