Find the exact value of cos−132.Write your answer in radians in terms of π.
Question
Find the exact value of cos−132.Write your answer in radians in terms of π.
Solution
The cosine function has a period of 2π, so cos(θ) = cos(θ + 2πn) for any integer n.
Given the angle -132, we first need to convert this from degrees to radians.
-132 degrees = -132 * (π/180) = -22π/30 = -11π/15 radians.
Now, we need to find an equivalent angle that lies within the range of [0, 2π). We can do this by adding multiples of 2π until we get an angle in this range.
-11π/15 + 2π = -11π/15 + 30π/15 = 19π/15.
So, cos(-132) = cos(19π/15).
Now, we need to find the reference angle. The reference angle is the acute angle that the terminal side of the given angle makes with the x-axis. Since 19π/15 is in the fourth quadrant, the reference angle is 2π - 19π/15 = 1π/15.
In the fourth quadrant, cosine is positive, so cos(-132) = cos(19π/15) = cos(1π/15).
Therefore, the exact value of cos(-132) in radians in terms of π is cos(1π/15).
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