Given:Na2O + CO2 + H2O ⟶ NaHCO3How many grams of sodium oxide are needed to produce 1,070 grams of sodium bicarbonate?Write your final answer in two decimal places.Use the following mass numbers:Na - 23O - 16C - 12H - 1
Question
Given:Na2O + CO2 + H2O ⟶ NaHCO3How many grams of sodium oxide are needed to produce 1,070 grams of sodium bicarbonate?Write your final answer in two decimal places.Use the following mass numbers:Na - 23O - 16C - 12H - 1
Solution
To solve this problem, we first need to determine the molar mass of each compound involved in the reaction.
- Sodium Oxide (Na2O): The molar mass is calculated as (2*23) + 16 = 62 g/mol
- Sodium Bicarbonate (NaHCO3): The molar mass is calculated as (23) + 1 + 12 + (3*16) = 84 g/mol
The balanced chemical equation is Na2O + CO2 + H2O ⟶ 2NaHCO3. This tells us that one mole of sodium oxide reacts to produce two moles of sodium bicarbonate.
Therefore, the ratio of the mass of sodium oxide to the mass of sodium bicarbonate is (62 g/mol) / (2*84 g/mol) = 0.369 g/g.
To find out how many grams of sodium oxide are needed to produce 1,070 grams of sodium bicarbonate, we multiply the given mass of sodium bicarbonate by the ratio we just calculated:
1,070 g * 0.369 g/g = 394.93 g
So, you would need approximately 394.93 grams of sodium oxide to produce 1,070 grams of sodium bicarbonate.
Similar Questions
<ol> <li>Mole Calculation Review:</li> </ol> <p>a. To calculate the number of moles from grams, we use the formula:</p> <p>moles = mass (g) / molar mass (g/mol)</p> <p>The molar mass of NaCl (Sodium Chloride) is approximately 58.44 g/mol and the molar mass of Na2CO3 (Sodium Carbonate) is approximately 105.99 g/mol.</p> <p>i. For 55 g of NaCl:</p> <pre><code> moles = 55 g / 58.44 g/mol = 0.94 moles </code></pre> <p>ii. For 0.025 g of Na2CO3:</p> <pre><code> moles = 0.025 g / 105.99 g/mol = 0.00024 moles </code></pre> <p>b. To calculate the mass in grams from moles, we use the formula:</p> <p>mass (g) = moles * molar mass (g/mol)</p> <p>i. For 0.5 moles of NaCl:</p> <pre><code> mass = 0.5 moles * 58.44 g/mol = 29.22 g </code></pre> <p>ii. For 2.11 moles of Na2CO3:</p> <pre><code> mass = 2.11 moles * 105.99 g/mol = 223.64 g </code></pre> <ol start="2"> <li>Molarity (mol/L) is a measure of concentration. It represents the number of moles of a substance per liter of solution.</li> </ol> <p>a. mol/L means moles per liter. It is a unit of concentration that tells us how many moles of a substance are present in one liter of solution.</p> <p>b. mol/L and grams/liter are both measures of concentration. The main difference between them is what they are measuring. mol/L measures the number of moles of a substance per liter of solution, while grams/liter measures the mass of the substance per liter of solution. The similarity is that both are used to express the concentration of a solution. However, mol/L takes into account the molecular weight of the substance, while grams/liter does not.</p> ####
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