A cube floats in water with 1/3rd part is outside the surface of water and it floats in another liquid with 3/4th part is outside the liquid then the density of liquid is
Question
A cube floats in water with 1/3rd part is outside the surface of water and it floats in another liquid with 3/4th part is outside the liquid then the density of liquid is
Solution
The density of a substance is defined as its mass per unit volume. When an object floats in a liquid, the volume of the object submerged is proportional to the density of the liquid.
Given that the cube floats in water with 1/3rd part outside, this means that 2/3rd of the cube is submerged in water. Since the density of water is 1 g/cm^3, we can say that the density of the cube is also 1 g/cm^3 (because it floats in water).
When the cube floats in another liquid with 3/4th part outside, this means that 1/4th of the cube is submerged in the liquid.
We can set up the following equation to find the density of the liquid:
(Density of the cube) = (Density of the liquid) * (Volume of the cube submerged in the liquid / Total volume of the cube)
1 g/cm^3 = (Density of the liquid) * (1/4)
Solving for the density of the liquid, we get:
Density of the liquid = 4 g/cm^3
So, the density of the liquid is 4 g/cm^3.
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