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In a redox reaction, Mn in (+7) oxidation state is reduced to _____ oxidation state in acidic medium.

Question

In a redox reaction, Mn in (+7) oxidation state is reduced to _____ oxidation state in acidic medium.

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Solution 1

In a redox reaction, Mn in (+7) oxidation state is reduced to (+2) oxidation state in acidic medium.

Here's the step by step process:

  1. Mn in +7 oxidation state is usually present as permanganate ion (MnO4-) in acidic medium.
  2. The reduction half-reaction in acidic medium is: MnO4- + 8H+ + 5e- -> Mn2+ + 4H2O
  3. This shows that Mn is reduced from +7 oxidation state to +2 oxidation state.

So, the answer is +2.

This problem has been solved

Solution 2

In a redox reaction, Mn in (+7) oxidation state is reduced to (+2) oxidation state in acidic medium.

Here are the steps:

  1. Identify the oxidation states: Mn starts in a +7 oxidation state.

  2. Identify the reduction process: Reduction is a process in which a substance gains electrons. In this case, Mn is being reduced.

  3. Determine the final oxidation state: In an acidic medium, Mn is typically reduced to a +2 oxidation state.

So, Mn in (+7) oxidation state is reduced to (+2) oxidation state in acidic medium.

This problem has been solved

Similar Questions

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In the redox reactionMnO2 + 4HCl → MnCl2 + 2H2O + Cl

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