A cyclist with a mass of 60 kg is riding at a speed of 8 m/s. What is the kinetic energy of the cyclist?*1 pointa) 240 Jb) 480 Jc) 960 Jd) 1920 J
Question
A cyclist with a mass of 60 kg is riding at a speed of 8 m/s. What is the kinetic energy of the cyclist?*1 pointa) 240 Jb) 480 Jc) 960 Jd) 1920 J
Solution
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * v^2
where: m is the mass of the object (in this case, the cyclist), and v is the speed of the object (in this case, the speed of the cyclist).
Given in the problem, m = 60 kg and v = 8 m/s.
Substituting these values into the formula gives:
KE = 1/2 * 60 kg * (8 m/s)^2 = 1/2 * 60 kg * 64 m^2/s^2 = 1920 Joules
So, the kinetic energy of the cyclist is 1920 Joules. Therefore, the correct answer is d) 1920 J.
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