To solve this problem, we can break it down into steps:

1. The father first goes 60m East.
2. Then he turns right (which would be South in this context) and goes 40m.
3. He turns right again (this time going West) and goes 30m. At this point, he is 30m West of the point 40m South of his starting point.
4. Finally, he goes 80m North and finds his son. This would place him 40m North of his starting point (since he had initially gone 40m South) and 30m West of it.

To find the distance from his starting point, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Here, the two sides are 30m (West) and 40m (North), and we're trying to find the hypotenuse (the straight-line distance from the starting point).

So, we calculate the square root of (30m^2 + 40m^2) = square root of (900m^2 + 1600m^2) = square root of 2500m^2 = 50m.

So, the father met his son 50m away from the starting point.

Question

To solve this problem, we can break it down into steps:

1. The father first goes 60m East.
2. Then he turns right (which would be South in this context) and goes 40m.
3. He turns right again (this time going West) and goes 30m. At this point, he is 30m West of the point 40m South of his starting point.
4. Finally, he goes 80m North and finds his son. This would place him 40m North of his starting point (since he had initially gone 40m South) and 30m West of it.

To find the distance from his starting point, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Here, the two sides are 30m (West) and 40m (North), and we're trying to find the hypotenuse (the straight-line distance from the starting point).

So, we calculate the square root of (30m^2 + 40m^2) = square root of (900m^2 + 1600m^2) = square root of 2500m^2 = 50m.

So, the father met his son 50m away from the starting point.

Knowee AI · Accepted Answer

To solve this problem, we can break it down into steps:

1. The father first goes 60m East.
2. Then he turns right (which would be South in this context) and goes 40m.
3. He turns right again (this time going West) and goes 30m. At this point, he is 30m West of the point 40m South of his starting point.
4. Finally, he goes 80m North and finds his son. This would place him 40m North of his starting point (since he had initially gone 40m South) and 30m West of it.

To find the distance from his starting point, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Here, the two sides are 30m (West) and 40m (North), and we're trying to find the hypotenuse (the straight-line distance from the starting point).

So, we calculate the square root of (30m^2 + 40m^2) = square root of (900m^2 + 1600m^2) = square root of 2500m^2 = 50m.

So, the father met his son 50m away from the starting point.

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