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Ravi has a bag with 8 balls numbered 1 through 8. He is playing a game of chance.This game is this: Ravi chooses one ball from the bag at random. He wins $1 if the number 1 is selected, $2 if the number 2 is selected, $5 if the number 3 is selected, $6 if the number 4 is selected, $8 if the number 5 is selected, and $10 if the number 6 is selected. He loses $14 if 7 or 8 is selected.(If necessary, consult a list of formulas.)(a) Find the expected value of playing the game.dollars(b) What can Ravi expect in the long run, after playing the game many times?(He replaces the ball in the bag each time.)Ravi can expect to gain money.Hecanexpecttowindollarsperselection.Ravi can expect to lose money.Hecanexpecttolosedollarsperselection.Ravi can expect to break even (neither gain nor lose money).

Question

Ravi has a bag with 8 balls numbered 1 through 8. He is playing a game of chance.This game is this: Ravi chooses one ball from the bag at random. He wins 1ifthenumber1isselected,1 if the number 1 is selected, 2 if the number 2 is selected, 5ifthenumber3isselected,5 if the number 3 is selected, 6 if the number 4 is selected, 8ifthenumber5isselected,and8 if the number 5 is selected, and 10 if the number 6 is selected. He loses $14 if 7 or 8 is selected.(If necessary, consult a list of formulas.)(a) Find the expected value of playing the game.dollars(b) What can Ravi expect in the long run, after playing the game many times?(He replaces the ball in the bag each time.)Ravi can expect to gain money.Hecanexpecttowindollarsperselection.Ravi can expect to lose money.Hecanexpecttolosedollarsperselection.Ravi can expect to break even (neither gain nor lose money).

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Solution

To find the expected value of playing the game, we need to multiply each outcome by its probability and then sum these values.

The probabilities for each outcome are as follows:

  • The probability of drawing a ball numbered 1 through 6 is 1/8 for each ball, since there are 8 balls in total.
  • The probability of drawing a ball numbered 7 or 8 is 2/8 or 1/4, since there are 2 balls out of 8 that could result in this outcome.

The expected value is then calculated as follows:

E(X) = (1/8)1+(1/8)1 + (1/8)*2 + (1/8)5+(1/8)5 + (1/8)*6 + (1/8)8+(1/8)8 + (1/8)*10 - (1/4)$14

E(X) = 0.125+0.125 + 0.25 + 0.625+0.625 + 0.75 + $1

This problem has been solved

Similar Questions

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