What will be the output of the following Python code?>>> a={i: 'A' + str(i) for i in range(5)}>>> aAn exception is thrown{0: ‘A0’, 1: ‘A1’, 2: ‘A2’, 3: ‘A3’, 4: ‘A4’}{0: ‘A’, 1: ‘A’, 2: ‘A’, 3: ‘A’, 4: ‘A’}{0: ‘0’, 1: ‘1’, 2: ‘2’, 3: ‘3’, 4: ‘4’}

What will be the output of the following Python code?a={1:"A",2:"B",3:"C"}for i in a: print(i,end=" ")1 2 3‘A’ ‘B’ ‘C’1 ‘A’ 2 ‘B’ 3 ‘C’Error, it should be: for i in a.items():

What will be the output of the following Python code snippet?print([[i+j for i in "abc"] for j in "def"])[‘da’, ‘ea’, ‘fa’, ‘db’, ‘eb’, ‘fb’, ‘dc’, ‘ec’, ‘fc’][[‘ad’, ‘bd’, ‘cd’], [‘ae’, ‘be’, ‘ce’], [‘af’, ‘bf’, ‘cf’]][[‘da’, ‘db’, ‘dc’], [‘ea’, ‘eb’, ‘ec’], [‘fa’, ‘fb’, ‘fc’]][‘ad’, ‘ae’, ‘af’, ‘bd’, ‘be’, ‘bf’, ‘cd’, ‘ce’, ‘cf’]

What will be the output of the following Python code snippet?ct = [0, 1, 2, 3]for ct[-1] in ct:    print(ct[-1], end = " ")Optionserror0 1 2 20 1 2 33 3 3 3

What will be the output of the following Python code snippet?a={1:"A",2:"B",3:"C"}a.setdefault(4,"D")print(a){1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}NoneError[1,3,6,10]

9. What will be the output of the following Python code?x = (i for i in range(3))for i in x:    print(i)for i in x:    print(i)