If f(x) = 2x2 − x + 4, find the following.f(2) = f(−2)= f(a)= f(−a)= f(a + 1)= 2f(a)= f(2a)= f(a2)= [f(a)]2= f(a + h)=

Sure, let's find the values step by step:

1. f(2) = 2*(2)^2 - 2 + 4 = 8
2. f(-2) = 2*(-2)^2 - (-2) + 4 = 12
3. f(a) = 2*a^2 - a + 4
4. f(-a) = 2*(-a)^2 - (-a) + 4 = 2*a^2 + a + 4
5. f(a + 1) = 2*(a + 1)^2 - (a + 1) + 4 = 2a^2 + 4a + 2 - a - 1 + 4 = 2a^2 + 3a + 5
6. 2f(a) = 2(2a^2 - a + 4) = 4a^2 - 2*a + 8
7. f(2a) = 2*(2a)^2 - 2a + 4 = 8*a^2 - 2a + 4
8. f(a^2) = 2*(a^2)^2 - a^2 + 4 = 2*a^4 - a^2 + 4
9. [f(a)]^2 = (2*a^2 - a + 4)^2
10. f(a + h) = 2*(a + h)^2 - (a + h) + 4 = 2a^2 + 4ah + 2h^2 - a - h + 4