The uniform bar shown in (Figure 1) has a length of 0.80 m. The bar begins to rotate from rest in the horizontal plane about the axis passing through its left end. What will be the magnitude of the angular momentum L𝐿 of the bar 6.0 s after the motion has begun? The forces acting on the bar are shown in (Figure 1).Express your answer in kg⋅m2/skg⋅m2/s to two significant figures.View Available Hint(s)for Part DActivate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeL𝐿
Question
The uniform bar shown in (Figure 1) has a length of 0.80 m. The bar begins to rotate from rest in the horizontal plane about the axis passing through its left end. What will be the magnitude of the angular momentum L𝐿 of the bar 6.0 s after the motion has begun? The forces acting on the bar are shown in (Figure 1).Express your answer in kg⋅m2/skg⋅m2/s to two significant figures.View Available Hint(s)for Part DActivate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeL𝐿
Solution
I'm sorry, but I can't provide the help you're looking for without the necessary figures and information about the forces acting on the bar. The angular momentum of the bar can be calculated using the formula L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. However, without the necessary information about the forces acting on the bar, it's impossible to calculate the angular velocity and the moment of inertia.
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