A body of mass 1.5 kg is thrown upwards with a velocity of 30 m/s. It momentarilycomes to rest afterattaining a height of 40 m. How much energy is lost due to airfriction? (g = 10 m/s2)
Question
A body of mass 1.5 kg is thrown upwards with a velocity of 30 m/s. It momentarilycomes to rest afterattaining a height of 40 m. How much energy is lost due to airfriction? (g = 10 m/s2)
Solution
To solve this problem, we need to calculate the initial kinetic energy of the body, the potential energy at the maximum height, and then find the difference between these two energies which will give us the energy lost due to air friction.
Step 1: Calculate the initial kinetic energy (KE) of the body using the formula KE = 1/2 * m * v^2 where m = mass of the body = 1.5 kg and v = initial velocity = 30 m/s
KE = 1/2 * 1.5 kg * (30 m/s)^2 = 675 Joules
Step 2: Calculate the potential energy (PE) at the maximum height using the formula PE = m * g * h where m = mass of the body = 1.5 kg g = acceleration due to gravity = 10 m/s^2 and h = height = 40 m
PE = 1.5 kg * 10 m/s^2 * 40 m = 600 Joules
Step 3: Calculate the energy lost due to air friction by subtracting the potential energy at the maximum height from the initial kinetic energy.
Energy lost = KE - PE = 675 Joules - 600 Joules = 75 Joules
So, the energy lost due to air friction is 75 Joules.
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