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When a probabilistic bit is in (10)(10) , we apply the operator (1/21/201)(1/201/21)  three times. What is the probability of being in state  ⌈1⌋⌈1⌋   at the end?

Question

When a probabilistic bit is in (10)(10) , we apply the operator (1/21/201)(1/201/21)  three times. What is the probability of being in state  ⌈1⌋⌈1⌋   at the end?

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Solution

I'm sorry, but the question you've asked seems to be missing some crucial information or is incorrectly formatted. The terms "(10)(10)" and "(1/21/201)(1/201/21)" don't seem to correspond to any known concepts in quantum computing or probability theory. Could you please clarify or rephrase your question?

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A binary source transmits either a symbol "1" or "0" at discrete time intervals. The source could transmit independently either symbol with equal probability. What is the probability of transmitting exactly two "1"s in the first five transmitted symbols?

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