Find the x-coordinate of vertex of the following quadratic function. 𝑓(𝑥)=−1𝑥2+4𝑥+5
Question
Find the x-coordinate of vertex of the following quadratic function. 𝑓(𝑥)=−1𝑥2+4𝑥+5
Solution
The vertex of a quadratic function is given by the formula -b/2a.
In the given quadratic function f(x) = -1x^2 + 4x + 5, the coefficient a is -1 and the coefficient b is 4.
Substituting these values into the formula, we get:
Vertex x-coordinate = -b/2a = -4/(2*-1) = 2
So, the x-coordinate of the vertex of the given quadratic function is 2.
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