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Acorporateteam-buildingeventcosts$ 8,plusanadditional$ 6perattendee.Howmanyattendeescantherebe,atmost,ifthebudgetforthecorporateteam-buildingeventis$ 50?

Question

Acorporateteam-buildingeventcosts8,plusanadditional 8,plusanadditional 6perattendee.Howmanyattendeescantherebe,atmost,ifthebudgetforthecorporateteam-buildingeventis$ 50?

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Solution

To solve this problem, you need to follow these steps:

  1. First, subtract the fixed cost of the event from the total budget. In this case, the fixed cost is 8andthetotalbudgetis8 and the total budget is 50. So, 5050 - 8 = $42.

  2. Next, divide the remaining budget by the cost per attendee. The cost per attendee is 6.So,6. So, 42 ÷ $6 = 7.

Therefore, the maximum number of attendees that can be accommodated within the budget is 7.

This problem has been solved

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