#01 bond makingThe following data give the energy needed to break the indicated bond. In the case of multiple bonds the energy applies to breaking the multiple bond completely. Bond formation, being the opposite, releases the same amount of heat from the chemical system.Bond Bond Dissociation EnergykJ/molBond Bond Dissociation EnergykJ/molC-H 413 C=O 745*C-C 347 C=C 614C-N 305 C≡C 839C-O 358 O=O 495O-H 463 N≡N 946 *C=O in carbon dioxide 804 kJ/molCalculate the heat released from the system on formation of 1.00 mol of the compound, methanal, CH2O from its individual atoms, 1 mol C, 2 mol H and 1 mol O. C + 2 H + O → CH2OMethanalQuestion 4Select one:a.1157 kJb.826 kJc.81 kJd.1571 kJe.745 kJ
Question
#01 bond makingThe following data give the energy needed to break the indicated bond. In the case of multiple bonds the energy applies to breaking the multiple bond completely. Bond formation, being the opposite, releases the same amount of heat from the chemical system.Bond Bond Dissociation EnergykJ/molBond Bond Dissociation EnergykJ/molC-H 413 C=O 745*C-C 347 C=C 614C-N 305 C≡C 839C-O 358 O=O 495O-H 463 N≡N 946 *C=O in carbon dioxide 804 kJ/molCalculate the heat released from the system on formation of 1.00 mol of the compound, methanal, CH2O from its individual atoms, 1 mol C, 2 mol H and 1 mol O. C + 2 H + O → CH2OMethanalQuestion 4Select one:a.1157 kJb.826 kJc.81 kJd.1571 kJe.745 kJ
Solution
To solve this problem, we need to calculate the total energy released when the bonds in methanal (CH2O) are formed.
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Formation of 2 C-H bonds: The bond dissociation energy for C-H is given as 413 kJ/mol. Since there are 2 C-H bonds in methanal, the total energy released is 2 * 413 = 826 kJ.
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Formation of 1 C=O bond: The bond dissociation energy for C=O is given as 745 kJ/mol. Since there is 1 C=O bond in methanal, the total energy released is 1 * 745 = 745 kJ.
Adding these together, the total energy released when 1 mol of methanal is formed from its individual atoms is 826 kJ + 745 kJ = 1571 kJ.
So, the correct answer is d. 1571 kJ.
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