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An emf is induced by rotating a 1000 turn, 15 cm diameter coil in the Earth’s 5.00 × 10-5 T magnetic field.

Question

An emf is induced by rotating a 1000 turn, 15 cm diameter coil in the Earth’s 5.00 × 10-5 T magnetic field.

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Solution

It seems like you want to calculate the induced emf in a rotating coil. Here are the steps to do that:

  1. First, we need to calculate the area of the coil. The formula for the area of a circle is πr². The radius is half the diameter, so in this case, it's 0.15/2 = 0.075 m. So, the area is π*(0.075 m)² = 0.0177 m².

  2. The magnetic flux through the coil is given by the formula Φ = BAcos(θ), where B is the magnetic field strength, A is the area, and θ is the angle between the magnetic field lines and the normal (perpendicular) to the coil. Since the coil is rotating, the angle θ changes with time, and we can write θ = ωt, where ω is the angular velocity and t is time.

  3. The rate of change of the magnetic flux is then dΦ/dt = BA-sin(θ)dθ/dt = -BAωsin(ωt).

  4. According to Faraday's law of electromagnetic induction, the induced emf is given by the negative rate of change of the magnetic flux, i.e., emf = -dΦ/dt. So, the magnitude of the induced emf is |emf| = BAω*sin(ωt).

  5. However, we don't

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