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A string of mass 2000g and length 100metres is under tension of 150N. (i)  Determine the linear density of the string (iii) Velocity of wave in the stringa.0.02N/M (ii) 0.866m/sb.0.02N/M (ii) 8.00m/sc.0.4N/M (ii) 8.00m/sd.0.4N/M (ii) 0.0866m/se.0.2N/M (ii) 0.866m/sf.0.03N/M (ii) 8.86m/s

Question

A string of mass 2000g and length 100metres is under tension of 150N. (i)  Determine the linear density of the string (iii) Velocity of wave in the stringa.0.02N/M (ii) 0.866m/sb.0.02N/M (ii) 8.00m/sc.0.4N/M (ii) 8.00m/sd.0.4N/M (ii) 0.0866m/se.0.2N/M (ii) 0.866m/sf.0.03N/M (ii) 8.86m/s

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Solution

The question seems to be asking for two things:

(i) The linear density of the string (ii) The velocity of a wave in the string

Let's solve this step by step:

(i) The linear density (μ) of a string is defined as the mass per unit length. It can be calculated using the formula:

μ = mass/length

Given that the mass of the string is 2000g (or 2kg, since 1kg = 1000g) and the length is 100m, we can substitute these values into the formula:

μ = 2kg / 100m = 0.02kg/m

So, the linear density of the string is 0.02kg/m.

(ii) The velocity (v) of a wave in a string under tension can be calculated using the formula:

v = sqrt(T/μ)

where T is the tension in the string and μ is the linear density. Given that the tension is 150N and we've just calculated the linear density to be 0.02kg/m, we can substitute these values into the formula:

v = sqrt(150N / 0.02kg/m) = sqrt(7500 m²/s²) = 86.6 m/s

So, the velocity of the wave in the string is 86.6 m/s.

Therefore, none of the provided options match the calculated results.

This problem has been solved

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