If a person walks at 28 km/hr instead of 20 km/hr , he would have walked 30 km more . What is the actual distance travelled by him?
Question
If a person walks at 28 km/hr instead of 20 km/hr , he would have walked 30 km more . What is the actual distance travelled by him?
Solution 1
Let's solve this step by step:
Step 1: Let's assume the actual distance travelled by the person is 'D' km.
Step 2: The time taken to cover this distance 'D' at a speed of 20 km/hr is 'D/20' hours.
Step 3: According to the problem, if the person walks at 28 km/hr instead of 20 km/hr, he would have walked 30 km more. So, the time taken to cover this extra 30 km at a speed of 28 km/hr is also 'D/20' hours.
Step 4: We can set up the equation from step 3 as follows: D/20 = (D+30)/28
Step 5: Solving this equation for 'D' gives us D = 210 km.
So, the actual distance travelled by the person is 210 km.
Solution 2
Let's solve this step by step:
Step 1: Let's assume the actual distance travelled by the person is 'D' km.
Step 2: The time taken to cover this distance 'D' at a speed of 20 km/hr is 'D/20' hours.
Step 3: According to the problem, if the person walks at 28 km/hr instead of 20 km/hr, he would have walked 30 km more. So, the time taken to cover this additional 30 km at a speed of 28 km/hr is also 'D/20' hours.
Step 4: We can set up the equation from step 3 as follows: D/20 = (D+30)/28
Step 5: Solving this equation for 'D' gives us the actual distance travelled by the person.
Cross multiply to get: 28D = 20D + 600
Step 6: Simplify to find the value of 'D': 28D - 20D = 600, so 8D = 600
Step 7: Finally, solve for 'D': D = 600 / 8 = 75 km
So, the actual distance travelled by the person is 75 km.
Solution 3
Let's solve this step by step:
Step 1: Let's assume the actual distance travelled by the person is 'D' km.
Step 2: The time taken to cover this distance 'D' at a speed of 20 km/hr is 'D/20' hours.
Step 3: According to the problem, if the person walks at 28 km/hr instead of 20 km/hr, he would have walked 30 km more. So, the time taken to cover this extra 30 km at a speed of 28 km/hr is also 'D/20' hours.
Step 4: We can set up the equation from step 3 as follows: D/20 = (D+30)/28
Step 5: Solving this equation for 'D' gives us D = 105 km.
So, the actual distance travelled by the person is 105 km.
Solution 4
Let's solve this step by step:
Step 1: Let's assume the actual distance travelled by the person is 'D' km.
Step 2: The time taken to travel this distance 'D' at a speed of 20 km/hr is 'D/20' hours.
Step 3: According to the problem, if the person walks at 28 km/hr instead of 20 km/hr, he would have walked 30 km more. So, the time taken to travel this extra 30 km at a speed of 28 km/hr is also 'D/20' hours.
Step 4: We can set up the equation from step 3 as follows: D/20 = (D+30)/28
Step 5: Solving this equation for 'D' gives us the actual distance travelled by the person.
Step 6: Multiply both sides of the equation by 20*28 to get rid of the denominators: 28D = 20D + 600
Step 7: Simplify the equation to find the value of 'D': 28D - 20D = 600, so 8D = 600
Step 8: Finally, solve for 'D': D = 600 / 8 = 75 km
So, the actual distance travelled by the person is 75 km.
Solution 5
Let's solve this step by step:
Step 1: Let's assume the actual distance travelled by the person is 'D' km.
Step 2: The time taken to cover this distance 'D' at a speed of 20 km/hr is 'D/20' hours.
Step 3: According to the problem, if the person walks at 28 km/hr instead of 20 km/hr, he would have walked 30 km more. So, the time taken to cover this additional distance at a speed of 28 km/hr is the same as the time taken to cover the actual distance 'D' at a speed of 20 km/hr. Therefore, we can write this as 'D/20 = (D+30)/28'.
Step 4: Now, we can solve this equation for 'D'. Multiply both sides by 20*28 to get rid of the denominators: 28D = 20D + 600.
Step 5: Simplify this to get: 8D = 600.
Step 6: Finally, solve for 'D': D = 600 / 8 = 75 km.
So, the actual distance travelled by the person is 75 km.
Solution 6
Sure, let's solve this step by step:
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First, let's denote the actual distance the person walked as "D" (in km), and the time he spent walking as "T" (in hours).
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According to the problem, we know that the person's usual speed is 20 km/hr. So, we can express the time he spent walking as T = D/20.
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The problem also tells us that if the person walked at a speed of 28 km/hr, he would have walked 30 km more. So, we can express this hypothetical distance as D + 30 = 28T.
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Now, we can substitute the expression for T from step 2 into the equation from step 3. This gives us D + 30 = 28(D/20).
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Simplifying this equation gives us D + 30 = 1.4D.
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Solving for D, we subtract D from both sides to get 30 = 0.4D.
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Finally, dividing both sides by 0.4 gives us D = 75 km.
So, the actual distance the person walked is 75 km.
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