Based on a random sample of n = 2345, the 95% confidence interval of variable X is (7.25, 9.12). You expect that the mean in the population is different from 7 at α = 0.05. What can you conclude?1 pointNothing, because you have not enough data to determine that.The value in the population is indeed different from 7.You cannot reject the null hypothesis.This confidence interval is wrong.

You have taken a random sample of size =n22 from a normal population that has a population mean of =μ95 and a population standard deviation of =σ8. Your sample, which is Sample 1 in the table below, has a mean of =x93.9. (In the table, Sample 1 is written "S1", Sample 2 is written "S2", etc.)(a)Based on Sample 1, graph the 75% and 90% confidence intervals for the population mean. Use 1.150 for the critical value for the 75% confidence interval, and use 1.645 for the critical value for the 90% confidence interval. (If necessary, consult a list of formulas.)Enter the lower and upper limits on the graphs to show each confidence interval. Write your answers with one decimal place.For the points ( and ), enter the population mean, =μ95.75% confidence interval87.0102.0 90% confidence interval87.0102.0(b)Press the "Generate Samples" button below to simulate taking 19 more samples of size =n22 from the population. Notice that the confidence intervals for these samples are drawn automatically. Then complete parts (c) and (d) below the table.x 75%lowerlimit 75%upperlimit 90%lowerlimit 90%upperlimitS1 93.9 ? ? ? ?S2 94.8 92.8 96.8 92.0 97.6S3 94.5 92.5 96.5 91.7 97.3S4 98.7 96.7 100.7 95.9 101.5S5 94.3 92.3 96.3 91.5 97.1S6 94.6 92.6 96.6 91.8 97.4S7 94.6 92.6 96.6 91.8 97.4S8 95.8 93.8 97.8 93.0 98.6S9 97.4 95.4 99.4 94.6 100.2S10 96.1 94.1 98.1 93.3 98.9S11 92.6 90.6 94.6 89.8 95.4S12 96.0 94.0 98.0 93.2 98.8S13 94.5 92.5 96.5 91.7 97.3S14 91.1 89.1 93.1 88.3 93.9S15 96.2 94.2 98.2 93.4 99.0S16 91.4 89.4 93.4 88.6 94.2S17 96.0 94.0 98.0 93.2 98.8S18 94.1 92.1 96.1 91.3 96.9S19 94.2 92.2 96.2 91.4 97.0S20 94.1 92.1 96.1 91.3 96.975% confidence intervals87.0102.090% confidence intervals87.0102.0(c)Notice that for =172085% of the samples, the 90% confidence interval contains the population mean. Choose the correct statement. When constructing 90% confidence intervals for 20 samples of the same size from the population, exactly 90% of the samples will contain the population mean. When constructing 90% confidence intervals for 20 samples of the same size from the population, at most 90% of the samples will contain the population mean. When constructing 90% confidence intervals for 20 samples of the same size from the population, it is possible that more or fewer than 90% of the samples will contain the population mean.(d)Choose ALL that are true. The 90% confidence interval for Sample 8 does not indicate that 90% of the Sample 8 data values are between 93.0 and 98.6. The 75% confidence interval for Sample 8 is narrower than the 90% confidence interval for Sample 8. This must be the case, because when a confidence interval is constructed for a sample, the greater the level of confidence, the wider the confidence interval. From the 75% confidence interval for Sample 8, we know that there is a 75% probability that the population mean is between 93.8 and 97.8. If there were a Sample 21 of size =n44 taken from the same population as Sample 8, then the 90% confidence interval for Sample 21 would be narrower than the 90% confidence interval for Sample 8. None of the choices above are true.

Use the given data to construct a 99.5% confidence interval for the population proportion p.=x52,  =n71Round the answer to at least three decimal places.Theconfidenceintervalis, .

A sample of 230 observations is selected from a normal population with a population standard deviation of 26. The sample mean is 18. (Use  t Distribution Table & z Distribution Table.)Required:a. Determine the standard error of the mean. (Round your answer to 3 decimal places.)c. Determine the 99% confidence interval for the population mean. (Round your answers to 3 decimal places.)

A sample of size =n92 is drawn from a normal population whose standard deviation is =σ5.1. The sample mean is =x35.33.Part 1 of 2(a) Construct a 99.9% confidence interval for μ. Round the answer to at least two decimal places.A 99.9% confidence interval for the mean is 33.58<<μ37.08.Part: 1 / 21 of 2 Parts CompletePart 2 of 2(b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid? Explain.The confidence interval constructed in part (a) ▼(Choose one) be valid since the sample size ▼(Choose one) larg

A student was asked to find a 95% confidence interval for widget width using data from a random sample of size n = 27. Which of the following is a correct interpretation of the interval 13.1 < μ < 25.9?Check all that are correct.There is a 95% chance that the mean of the population is between 13.1 and 25.9.With 95% confidence, the mean width of all widgets is between 13.1 and 25.9.With 95% confidence, the mean width of a randomly selected widget will be between 13.1 and 25.9.There is a 95% chance that the mean of a sample of 27 widgets will be between 13.1 and 25.9.The mean width of all widgets is between 13.1 and 25.9, 95% of the time. We know this is true because the mean of our sample is between 13.1 and 25.9.