Boyle's Law can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Step 1: Identify the known values.
P1 = 230 kPa
V1 = 7 L
V2 = 2 L

Step 2: Substitute the known values into the equation and solve for P2.
230 kPa * 7 L = P2 * 2 L

Step 3: Solve for P2.
P2 = (230 kPa * 7 L) / 2 L = 805 kPa

So, the pressure when the volume is 2 L is 805 kPa.

Question

Boyle's Law can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Step 1: Identify the known values.
P1 = 230 kPa
V1 = 7 L
V2 = 2 L

Step 2: Substitute the known values into the equation and solve for P2.
230 kPa * 7 L = P2 * 2 L

Step 3: Solve for P2.
P2 = (230 kPa * 7 L) / 2 L = 805 kPa

So, the pressure when the volume is 2 L is 805 kPa.

Knowee AI · Accepted Answer

Boyle's Law can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Step 1: Identify the known values.
P1 = 230 kPa
V1 = 7 L
V2 = 2 L

Step 2: Substitute the known values into the equation and solve for P2.
230 kPa * 7 L = P2 * 2 L

Step 3: Solve for P2.
P2 = (230 kPa * 7 L) / 2 L = 805 kPa

So, the pressure when the volume is 2 L is 805 kPa.

Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 7 L, the pressure is 230 kPa (kilopascals). What is the pressure when the volume is 2 L ?