What is The Output of the following program? #include<stdio.h> void main() { int i = printf("00"); int i =printf("00"); printf("%d",i); } 0 00 002

The output of the program will be "002". Here's why:

1. The printf function returns the number of characters printed. So, when you do int i = printf("00");, it prints "00" and returns 2 (the number of characters printed), which is then stored in i.

2. However, you have a duplicate declaration of i in the same scope, which is not allowed in C. So, the program should actually give a compile error.

But if we assume that the second declaration of i is a mistake and ignore it, then the printf("%d",i); will print the value of i, which is 2.

So, the output will be "002".