. An electron revolving around H-nucleus in the ground state absorbs 10.2 eV energy. Itsangular momentum increases by

The energy absorbed by the electron is used to move it to a higher energy level. The angular momentum of an electron in an atom is quantized and given by the formula:

L = √n(h/2π)

where: L is the angular momentum, n is the principal quantum number (energy level), h is Planck's constant.

When the electron absorbs energy, it moves to a higher energy level. The difference in angular momentum between two energy levels is given by the difference in their quantum numbers.

Let's say the electron moves from energy level n1 to n2. The change in angular momentum is then:

ΔL = L2 - L1 = √n2(h/2π) - √n1(h/2π)

Given that the energy difference between the two levels is 10.2 eV, we can use the formula for the energy levels of a hydrogen atom:

En = -13.6 eV/n²

So, the energy difference is:

ΔE = E2 - E1 = -13.6 eV/n2² + 13.6 eV/n1²

Setting this equal to 10.2 eV and solving for n2 (assuming n1 = 1 for the ground state), we find that n2 = 2.

Substituting these values into the formula for ΔL, we find:

ΔL = √2(h/2π) - √1(h/2π) = (1.41 - 1)(h/2π) = 0.41(h/2π)

This is the increase in angular momentum of the electron.