This problem can be solved using Python programming language. Here is a step-by-step solution: Step 1: First, we need to take the input for the number of movies (N) and the number of days (D). We can use the `input()` function in Python for this. ```python N = int(input()) # Number of movies D = int(input()) # Number of days ``` Step 2: We need to check if the number of movies is greater than 1. If not, we print "Movie rating cannot be done for one movie" and end the program. ```python if N max_rating: max_rating = ratings[j][i] max_movie = j print(f"Day {i+1} movie {max_movie+1} rating {max_rating}") ``` This will print the movie position in the matrix that received the highest rating for each day. If more than one movie has the highest rating for a particular day, it will print the movie that was rated first.

Question

This problem can be solved using Python programming language. Here is a step-by-step solution:

Step 1: First, we need to take the input for the number of movies (N) and the number of days (D). We can use the `input()` function in Python for this.

```python
N = int(input())  # Number of movies
D = int(input())  # Number of days
```

Step 2: We need to check if the number of movies is greater than 1. If not, we print "Movie rating cannot be done for one movie" and end the program.

```python
if N <= 1:
    print("Movie rating cannot be done for one movie")
    exit()
```

Step 3: If the number of movies is greater than 1, we need to take the ratings for each movie for each day. We can use a 2D list (list of lists) in Python to store these ratings.

```python
ratings = []
for i in range(N):
    ratings.append(list(map(int, input().split())))
```

Step 4: Now, we need to find the movie with the highest rating for each day. We can do this by iterating over the 2D list and keeping track of the maximum rating and its position.

```python
for i in range(D):
    max_rating = -1
    max_movie = -1
    for j in range(N):
        if ratings[j][i] > max_rating:
            max_rating = ratings[j][i]
            max_movie = j
    print(f"Day {i+1} movie {max_movie+1} rating {max_rating}")
```

This will print the movie position in the matrix that received the highest rating for each day. If more than one movie has the highest rating for a particular day, it will print the movie that was rated first.

Knowee AI · Accepted Answer