A 2.300×103 kg car is parked on a steep hill inclined at 29.0o. What is the force of friction acting on the car? The coefficients of friction between the tires and the road are μk = 0.500 and μs = 0.800. 5.45×103 N 8.72×103 N 1.97×104 N 1.09×104 N

To solve this problem, we need to find the force of static friction, which is what keeps the car from sliding down the hill. The force of static friction (Fs) can be calculated using the equation:

Fs = μs * Fn

where μs is the coefficient of static friction and Fn is the normal force.

The normal force on an incline is given by:

Fn = m * g * cos(θ)

where m is the mass of the car, g is the acceleration due to gravity (9.8 m/s^2), and θ is the angle of the incline.

First, let's calculate the normal force:

Fn = (2.300×10^3 kg) * (9.8 m/s^2) * cos(29.0°) Fn = 2.300×10^3 kg * 9.8 m/s^2 * 0.875 Fn = 1.97×10^4 N

Then, we can calculate the force of static friction:

Fs = μs * Fn Fs = 0.800 * 1.97×10^4 N Fs = 1.576×10^4 N

So, the force of friction acting on the car is approximately 1.576×10^4 N. This is not one of the options given, so there may be a mistake in the problem or in the given options.

To solve this problem, we first need to calculate the force of gravity acting on the car. This is given by the equation F = m*g, where m is the mass of the car and g is the acceleration due to gravity.

1. Calculate the force of gravity (Fg): Fg = m * g Fg = 2.300 * 10^3 kg * 9.8 m/s^2 Fg = 22,540 N

Next, we need to calculate the component of the gravitational force that acts parallel to the incline. This is given by the equation F_parallel = Fg * sin(θ), where θ is the angle of the incline.

2. Calculate the parallel component of the gravitational force (F_parallel): F_parallel = Fg * sin(θ) F_parallel = 22,540 N * sin(29.0°) F_parallel = 11,000 N

The force of static friction that prevents the car from sliding down the hill is given by the equation F_friction = μs * F_normal, where μs is the coefficient of static friction and F_normal is the normal force. In this case, the normal force is equal to the component of the gravitational force that acts perpendicular to the incline, which is given by Fg * cos(θ).

3. Calculate the normal force (F_normal): F_normal = Fg * cos(θ) F_normal = 22,540 N * cos(29.0°) F_normal = 19,500 N

4. Calculate the force of static friction (F_friction): F_friction = μs * F_normal F_friction = 0.800 * 19,500 N F_friction = 15,600 N

So, the force of friction acting on the car is 15,600 N. However, this value is not among the options given. It's possible that there's a mistake in the problem or in the given options.