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#include <iostream>using namespace std;int main() { int n; cin >> n; if (n < 1) { return 1; } int current_num = n * (n + 1) / 2; for (int row = 1; row <= n; row++) { int col_offset = 0; for (int col = 1; col <= row; col++) { cout << current_num - col_offset; if (col < row) { cout << " "; } else { cout << endl; } col_offset++; } current_num -= row; } return 0;}

Question

#include <iostream>using namespace std;int main() { int n; cin >> n; if (n < 1) { return 1; } int current_num = n * (n + 1) / 2; for (int row = 1; row <= n; row++) { int col_offset = 0; for (int col = 1; col <= row; col++) { cout << current_num - col_offset; if (col < row) { cout << " "; } else { cout << endl; } col_offset++; } current_num -= row; } return 0;}

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Solution

This is a C++ program. It reads an integer n from the input, and if n is less than 1, it returns 1 and ends the program. If n is greater than or equal to 1, it calculates the sum of the first n natural numbers and stores it in current_num.

Then it starts a loop from 1 to n (inclusive), where each iteration represents a row. For each row, it starts another loop from 1 to the current row number (inclusive), where each iteration represents a column.

In each column of each row, it prints the value of current_num minus the column offset (which starts from 0 and increments by 1 in each column), followed by three spaces if it's not the last column, or a newline character if it is.

After each row, it subtracts the row number from current_num.

The program ends by returning 0.

This problem has been solved

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