Sure, here is a Python program that checks if a given number is an Armstrong number or not using a while loop:

```python
# Function to check if a number is Armstrong
def is_armstrong(num):
# Initialize sum
sum = 0
# Find the number of digits
temp = num
while temp 0:
digit = temp % 10
sum += digit ** 3
temp //= 10

# If the sum is equal to the original number, it is an Armstrong number
if num == sum:
return True
return False

# Test the function
num = int(input("Enter a number: "))
if is_armstrong(num):
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")
```

This program works by taking a number as input and checking if it is an Armstrong number. An Armstrong number is a number that is equal to the sum of cubes of its digits. For example, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153. The program uses a while loop to calculate the sum of cubes of the digits of the number. If the sum is equal to the original number, the number is an Armstrong number.

Question

Sure, here is a Python program that checks if a given number is an Armstrong number or not using a while loop:

```python
# Function to check if a number is Armstrong
def is_armstrong(num):
    # Initialize sum
    sum = 0
    # Find the number of digits
    temp = num
    while temp > 0:
        digit = temp % 10
        sum += digit ** 3
        temp //= 10

# If the sum is equal to the original number, it is an Armstrong number
    if num == sum:
        return True
    return False

# Test the function
num = int(input("Enter a number: "))
if is_armstrong(num):
    print(num,"is an Armstrong number")
else:
    print(num,"is not an Armstrong number")
```

This program works by taking a number as input and checking if it is an Armstrong number. An Armstrong number is a number that is equal to the sum of cubes of its digits. For example, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153. The program uses a while loop to calculate the sum of cubes of the digits of the number. If the sum is equal to the original number, the number is an Armstrong number.

Knowee AI · Accepted Answer

Sure, here is a Python program that checks if a given number is an Armstrong number or not using a while loop:

```python
# Function to check if a number is Armstrong
def is_armstrong(num):
    # Initialize sum
    sum = 0
    # Find the number of digits
    temp = num
    while temp > 0:
        digit = temp % 10
        sum += digit ** 3
        temp //= 10

# If the sum is equal to the original number, it is an Armstrong number
    if num == sum:
        return True
    return False

# Test the function
num = int(input("Enter a number: "))
if is_armstrong(num):
    print(num,"is an Armstrong number")
else:
    print(num,"is not an Armstrong number")
```

This program works by taking a number as input and checking if it is an Armstrong number. An Armstrong number is a number that is equal to the sum of cubes of its digits. For example, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153. The program uses a while loop to calculate the sum of cubes of the digits of the number. If the sum is equal to the original number, the number is an Armstrong number.

Write a python program to check the given number is Armstrong or not usingwhile loop.

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