Select the correct answerA villager buys a goat and a sheep together for Rs.14,250. He sold the sheep at a profit of 10% and the goat at a loss of 20%. If he sold both the animals at the same price, then what was the cost price of the cheaper animal?Options8,2507,5006,0006,600
Question
Select the correct answerA villager buys a goat and a sheep together for Rs.14,250. He sold the sheep at a profit of 10% and the goat at a loss of 20%. If he sold both the animals at the same price, then what was the cost price of the cheaper animal?Options8,2507,5006,0006,600
Solution
Let's denote the cost price of the sheep as S and the cost price of the goat as G.
According to the problem, S + G = 14,250.
The sheep was sold at a profit of 10%, so its selling price was 1.1S. The goat was sold at a loss of 20%, so its selling price was 0.8G.
Since both animals were sold for the same price, we can set these two equations equal to each other:
1.1S = 0.8G
Now we have a system of two equations, and we can solve it step by step.
First, let's express S from the first equation: S = 14,250 - G.
Now we can substitute S in the second equation:
1.1(14,250 - G) = 0.8G
This simplifies to:
15,675 - 1.1G = 0.8G
Combine like terms:
15,675 = 1.9G
Finally, solve for G:
G = 15,675 / 1.9 ≈ 8,250
So, the cost price of the goat was approximately Rs.8,250.
Substitute G = 8,250 in the first equation to find S:
S = 14,250 - 8,250 = 6,000
So, the cost price of the sheep was Rs.6,000.
Therefore, the cost price of the cheaper animal was Rs.6,000.
So, the correct answer is 6,000.
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