The first three terms of a geometric sequence are:2, 6, 18, ...What is the 7th term?MG Algebra Exit Exam January BenchmarkPowered by Illuminate Education.Page 9 of 11
Question
The first three terms of a geometric sequence are:2, 6, 18, ...What is the 7th term?MG Algebra Exit Exam January BenchmarkPowered by Illuminate Education.Page 9 of 11
Solution
In a geometric sequence, each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio.
In this case, the common ratio (r) can be found by dividing the second term by the first term, or the third term by the second term.
So, r = 6/2 = 3 or r = 18/6 = 3.
The nth term of a geometric sequence can be found using the formula:
a_n = a * r^(n-1)
where: a_n is the nth term a is the first term r is the common ratio n is the term number
Substituting the given values into the formula, the 7th term (a_7) is:
a_7 = 2 * 3^(7-1) = 2 * 3^6 = 2 * 729 = 1458
So, the 7th term of the sequence is 1458.
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