To solve the system of equations y = |x| and y = 2x + 3, we need to consider the two cases for |x|, which are x = 0 and x = 0, |x| = x. So, we substitute y = x into the second equation to get x = 2x + 3. Solving this equation gives x = -3. However, this is not a valid solution because we assumed x = 0. So, there are no solutions in this case. 2. For x

Question

To solve the system of equations y = |x| and y = 2x + 3, we need to consider the two cases for |x|, which are x >= 0 and x < 0.

For x >= 0, |x| = x. So, we substitute y = x into the second equation to get x = 2x + 3. Solving this equation gives x = -3. However, this is not a valid solution because we assumed x >= 0. So, there are no solutions in this case.
For x < 0, |x| = -x. So, we substitute y = -x into the second equation to get -x = 2x + 3. Solving this equation gives x = -1. Substituting x = -1 into the first equation gives y = |-1| = 1.

So, the solution to the system of equations is (-1, 1).

Knowee AI · Accepted Answer

To solve the system of equations y = |x| and y = 2x + 3, we need to consider the two cases for |x|, which are x >= 0 and x < 0.

For x >= 0, |x| = x. So, we substitute y = x into the second equation to get x = 2x + 3. Solving this equation gives x = -3. However, this is not a valid solution because we assumed x >= 0. So, there are no solutions in this case.
For x < 0, |x| = -x. So, we substitute y = -x into the second equation to get -x = 2x + 3. Solving this equation gives x = -1. Substituting x = -1 into the first equation gives y = |-1| = 1.

So, the solution to the system of equations is (-1, 1).

Solve the system: y = |x|, y = 2x + 3