What will be the output of executing this code?public class MultipleCatchExample { public static void main(String[] args) { try { int[] numbers = {1, 2, 3}; System.out.println(numbers[5]); } catch (ArrayIndexOutOfBoundsException e) { System.out.println("Array index out of bounds."); } catch (Exception e) { System.out.println("An exception occurred: " + e); } }}a.Array index out of boundsb.Compilation Errorc.Array index out of bounds. An exception occurred: java.lang.ArrayIndexOutOfBoundsExceptiond.An exception occurred: java.lang.ArrayIndexOutOfBoundsException
Question
What will be the output of executing this code?public class MultipleCatchExample { public static void main(String[] args) { try { int[] numbers = {1, 2, 3}; System.out.println(numbers[5]); } catch (ArrayIndexOutOfBoundsException e) { System.out.println("Array index out of bounds."); } catch (Exception e) { System.out.println("An exception occurred: " + e); } }}a.Array index out of boundsb.Compilation Errorc.Array index out of bounds. An exception occurred: java.lang.ArrayIndexOutOfBoundsExceptiond.An exception occurred: java.lang.ArrayIndexOutOfBoundsException
Solution
The output of the code will be "Array index out of bounds." This is because the code is trying to access the 6th element of the array 'numbers' which only has 3 elements. This results in an ArrayIndexOutOfBoundsException. The catch block for this specific exception is executed first, printing "Array index out of bounds." The general Exception catch block is not executed because the specific exception has already been caught and handled. So, the correct answer is a. "Array index out of bounds."
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