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The radius of the second Bohr orbit for hydrogenatom is(Planck's Const. h = 6.6262 × 10 –34 Js;mass of electron = 9.1091 × 10–31 kg;charge of electron e = 1.60210 × 10–19 C;permittivity of vacuumH0 = 8.854185 × 10 –12 kg–1 m –3 A2)

Question

The radius of the second Bohr orbit for hydrogenatom is(Planck's Const. h = 6.6262 × 10 –34 Js;mass of electron = 9.1091 × 10–31 kg;charge of electron e = 1.60210 × 10–19 C;permittivity of vacuumH0 = 8.854185 × 10 –12 kg–1 m –3 A2)

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Solution

To find the radius of the second Bohr orbit for a hydrogen atom, we can use the formula:

r = (n^2 * h^2 * ε0) / (π * m * e^2)

where:

  • n is the principal quantum number (in this case, n = 2 for the second orbit)
  • h is Planck's constant (h = 6.6262 × 10^(-34) Js)
  • ε0 is the permittivity of vacuum (ε0 = 8.854185 × 10^(-12) kg^(-1) m^(-3) A^2)
  • m is the mass of the electron (m = 9.1091 × 10^(-31) kg)
  • e is the charge of the electron (e = 1.60210 × 10^(-19) C)

Plugging in the values, we have:

r = (2^2 * (6.6262 × 10^(-34) Js)^2 * (8.854185 × 10^(-12) kg^(-1) m^(-3) A^2)) / (π * (9.1091 × 10^(-31) kg) * (1.60210 × 10^(-19) C)^2)

Simplifying the expression, we can calculate the value of r.

This problem has been solved

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