Select the correct answerWhat will be the output of the following Java code? class Name { public static void main(String args[]) { try { int ct1 = 0; int ct2 = 5; int ct3 = ct2 / ct1; System.out.print("Hello"); } catch(Exception e) { System.out.print("CodeTantra"); } } }OptionsCodeTantraHelloHelloCodeTantraCompilation Error
Question
Select the correct answerWhat will be the output of the following Java code? class Name { public static void main(String args[]) { try { int ct1 = 0; int ct2 = 5; int ct3 = ct2 / ct1; System.out.print("Hello"); } catch(Exception e) { System.out.print("CodeTantra"); } } }OptionsCodeTantraHelloHelloCodeTantraCompilation Error
Solution
The correct answer is "CodeTantra".
Here's the step by step explanation:
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The main method is the entry point of the Java program.
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Inside the main method, a try-catch block is used to handle exceptions.
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In the try block, three integer variables ct1, ct2, and ct3 are declared. ct1 is initialized to 0 and ct2 is initialized to 5.
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Then, ct3 is calculated as the division of ct2 by ct1. Since ct1 is 0, this operation will throw an ArithmeticException because division by zero is undefined in mathematics.
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As soon as the exception is thrown, the program control is transferred to the catch block and the rest of the code in the try block is skipped.
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In the catch block, "CodeTantra" is printed to the console.
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Therefore, the output of the program is "CodeTantra".
Note: The "Hello" in the try block is not printed because the exception is thrown before this line of code is reached.
Similar Questions
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