Given the root of a perfect binary tree, reverse the node values at each odd level of the tree.For example, suppose the node values at level 3 are [2,1,3,4,7,11,29,18], then it should become [18,29,11,7,4,3,1,2].Return the root of the reversed tree.A binary tree is perfect if all parent nodes have two children and all leaves are on the same level.The level of a node is the number of edges along the path between it and the root node. Example 1:Input: root = [2,3,5,8,13,21,34]Output: [2,5,3,8,13,21,34]Explanation: The tree has only one odd level.The nodes at level 1 are 3, 5 respectively, which are reversed and become 5, 3.
Question
Given the root of a perfect binary tree, reverse the node values at each odd level of the tree.For example, suppose the node values at level 3 are [2,1,3,4,7,11,29,18], then it should become [18,29,11,7,4,3,1,2].Return the root of the reversed tree.A binary tree is perfect if all parent nodes have two children and all leaves are on the same level.The level of a node is the number of edges along the path between it and the root node. Example 1:Input: root = [2,3,5,8,13,21,34]Output: [2,5,3,8,13,21,34]Explanation: The tree has only one odd level.The nodes at level 1 are 3, 5 respectively, which are reversed and become 5, 3.
Solution
To solve this problem, we can use a breadth-first search (BFS) algorithm to traverse the binary tree level by level. Here are the steps:
- Initialize a queue and add the root node to the queue.
- Initialize a variable
levelto 1 to keep track of the current level. - While the queue is not empty, perform the following steps:
- Initialize an empty list
current_levelto store the nodes at the current level. - Get the size of the queue, which represents the number of nodes at the current level.
- For each node at the current level, remove it from the queue and add it to
current_level. - If
levelis odd, reverse the order of nodes incurrent_level. - For each node in
current_level, add its children to the queue. - Increment
levelby 1.
- Initialize an empty list
- Return the
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