5. An object’s mass of 9.11x10-31 kg is circling at a radius of 23.22 m. If there is a force of 3.60x10-16 N being applied, what is the object’s speed?
Question
- An object’s mass of 9.11x10-31 kg is circling at a radius of 23.22 m. If there is a force of 3.60x10-16 N being applied, what is the object’s speed?
Solution
To solve this problem, we can use the formula for centripetal force, which is F = mv^2/r, where F is the force, m is the mass, v is the speed, and r is the radius. We are given F, m, and r, and we need to solve for v.
Step 1: Substitute the given values into the formula:
3.60x10^-16 N = (9.11x10^-31 kg) * v^2 / 23.22 m
Step 2: Rearrange the formula to solve for v^2:
v^2 = (3.60x10^-16 N * 23.22 m) / 9.11x10^-31 kg
Step 3: Calculate the value of v^2:
v^2 = 9.12x10^14 m^2/s^2
Step 4: Take the square root of both sides to solve for v:
v = sqrt(9.12x10^14 m^2/s^2)
v = 9.54x10^7 m/s
So, the object's speed is approximately 9.54x10^7 m/s.
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