Containers A, B and C of equal volume contain oxygen, neon and methane respectively at thesame temperature and pressure. The correct increasing order of their rate of diffusion is(A) A < B < C (B) B < C < A(C) C < A < B (D) C < B < A

To determine the correct increasing order of the rate of diffusion for containers A, B, and C, we need to consider the molecular properties of oxygen, neon, and methane.

1. Oxygen (O2): Oxygen is a diatomic molecule with a molecular weight of 32 g/mol. It consists of two oxygen atoms bonded together.

2. Neon (Ne): Neon is a monatomic gas with a molecular weight of 20 g/mol. It consists of individual neon atoms.

3. Methane (CH4): Methane is a compound consisting of one carbon atom bonded to four hydrogen atoms. It has a molecular weight of 16 g/mol.

The rate of diffusion is inversely proportional to the square root of the molar mass of the gas. Therefore, the gas with the lowest molar mass will have the highest rate of diffusion.

Comparing the molar masses, we can see that neon has the lowest molar mass (20 g/mol), followed by methane (16 g/mol), and oxygen has the highest molar mass (32 g/mol).

Therefore, the correct increasing order of their rate of diffusion is: (C) C < A < B

In this order, methane (C) will have the highest rate of diffusion, followed by oxygen (A), and neon (B) will have the lowest rate of diffusion.