Consider milling a 31 [mm] depth slot in aflat surface of a work part using a slab milling cutter. The diameter of the cutter is 76 [mm], its width is 44 [mm] and it has 9 teeth. The cutter rotates at 576 [RPM]. Measurement of the chip thickness shows that feed rate is 0.02 [mm/tooth]. The length of the work part is 284 [mm]. The allowances at the beginning and end of the cut are 3 [mm]. MRR in [mm3/sec] is then given by _______ Question 1Answer20831906206420451831
Question
Consider milling a 31 [mm] depth slot in aflat surface of a work part using a slab milling cutter. The diameter of the cutter is 76 [mm], its width is 44 [mm] and it has 9 teeth. The cutter rotates at 576 [RPM]. Measurement of the chip thickness shows that feed rate is 0.02 [mm/tooth]. The length of the work part is 284 [mm]. The allowances at the beginning and end of the cut are 3 [mm]. MRR in [mm3/sec] is then given by _______ Question 1Answer20831906206420451831
Solution
To calculate the Material Removal Rate (MRR) in milling, we can use the formula:
MRR = Feed rate (mm/min) x Depth of cut (mm) x Width of cut (mm)
First, we need to calculate the feed rate. The feed rate is given by the product of the feed per tooth and the number of teeth and the RPM.
Feed rate = Feed per tooth x Number of teeth x RPM Feed rate = 0.02 mm/tooth x 9 teeth x 576 RPM = 103.68 mm/min
Next, we calculate the width of cut. The width of cut is equal to the width of the cutter, which is 44 mm.
Finally, the depth of cut is given as 31 mm.
Substituting these values into the MRR formula gives:
MRR = 103.68 mm/min x 31 mm x 44 mm = 141,654.72 mm^3/min
To convert this to mm^3/sec, we divide by 60 (since there are 60 seconds in a minute):
MRR = 141,654.72 mm^3/min ÷ 60 = 2360.91 mm^3/sec
So, the Material Removal Rate (MRR) is approximately 2360.91 mm^3/sec.
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