Which is an equation in point slope form that contains the points (-5, 1) and (-2, 6)?

The point-slope form of a line is given by the formula:

y - y1 = m(x - x1)

where m is the slope of the line and (x1, y1) is a point on the line.

First, we need to find the slope (m) of the line that passes through the points (-5, 1) and (-2, 6). The formula to find the slope between two points (x1, y1) and (x2, y2) is:

m = (y2 - y1) / (x2 - x1)

Substituting the given points into the formula, we get:

m = (6 - 1) / (-2 - (-5)) = 5 / 3

So, the slope of the line is 5/3.

Now, we can use the point-slope form to write the equation of the line. We can use either of the given points. If we use the point (-5, 1), the equation becomes:

y - 1 = 5/3 (x - (-5))

Simplifying this, we get:

y - 1 = 5/3x + 5*5/3

So, the equation of the line in point-slope form that contains the points (-5, 1) and (-2, 6) is:

y = 5/3x + 10 + 1

or

y = 5/3x + 11