Two unbiased dice are thrown simultaneously. the probability of getting the sum divisible by 3, is ?Question 2Answera.12/36b.11/36c.17/36d.13/36
Question
Two unbiased dice are thrown simultaneously. the probability of getting the sum divisible by 3, is ?Question 2Answera.12/36b.11/36c.17/36d.13/36
Solution
When two dice are thrown, the total number of outcomes is 36 (6 outcomes from the first die multiplied by 6 outcomes from the second die).
The sum of numbers on the dice can be divisible by 3 in the following cases: (1,2), (2,1), (1,5), (5,1), (2,4), (4,2), (3,3), (3,6), (6,3), (4,5), (5,4), (6,6). That's 12 favorable outcomes.
So, the probability of getting the sum divisible by 3 is the number of favorable outcomes divided by the total number of outcomes, which is 12/36 = 1/3.
Therefore, the correct answer is a. 12/36.
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