Here is a Python program that uses a do-while loop to solve the problem:

```python
def check_palindrome(n):
temp = n
odd = ""
while temp 0:
digit = temp % 10
if digit % 2 != 0:
odd = odd + str(digit)
temp = temp // 10
print("Odd digits: ", odd)
if odd == odd[::-1]:
print("The odd digits form a palindrome.")
else:
print("The odd digits do not form a palindrome.")

# Test cases
check_palindrome(12321)
check_palindrome(12345)
```

This program works by extracting each digit from the number, checking if it's odd, and if it is, adding it to a string. It then checks if this string is the same forwards and backwards (i.e., if it's a palindrome). If it is, it prints that the odd digits form a palindrome, otherwise it prints that they do not.

Note: Python does not have a built-in do-while loop like some other languages, so we use a while loop instead. The effect is the same.

Question

Here is a Python program that uses a do-while loop to solve the problem:

```python
def check_palindrome(n):
    temp = n
    odd = ""
    while temp > 0:
        digit = temp % 10
        if digit % 2 != 0:
            odd = odd + str(digit)
        temp = temp // 10
    print("Odd digits: ", odd)
    if odd == odd[::-1]:
        print("The odd digits form a palindrome.")
    else:
        print("The odd digits do not form a palindrome.")

# Test cases
check_palindrome(12321)
check_palindrome(12345)
```

This program works by extracting each digit from the number, checking if it's odd, and if it is, adding it to a string. It then checks if this string is the same forwards and backwards (i.e., if it's a palindrome). If it is, it prints that the odd digits form a palindrome, otherwise it prints that they do not.

Note: Python does not have a built-in do-while loop like some other languages, so we use a while loop instead. The effect is the same.

Knowee AI · Accepted Answer

Here is a Python program that uses a do-while loop to solve the problem:

```python
def check_palindrome(n):
    temp = n
    odd = ""
    while temp > 0:
        digit = temp % 10
        if digit % 2 != 0:
            odd = odd + str(digit)
        temp = temp // 10
    print("Odd digits: ", odd)
    if odd == odd[::-1]:
        print("The odd digits form a palindrome.")
    else:
        print("The odd digits do not form a palindrome.")

# Test cases
check_palindrome(12321)
check_palindrome(12345)
```

This program works by extracting each digit from the number, checking if it's odd, and if it is, adding it to a string. It then checks if this string is the same forwards and backwards (i.e., if it's a palindrome). If it is, it prints that the odd digits form a palindrome, otherwise it prints that they do not.

Note: Python does not have a built-in do-while loop like some other languages, so we use a while loop instead. The effect is the same.

Question

Solution

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