What is the binding energy of a nucleus that has a mass defect of 5.81 𝑥x 10-29 kg?A.5.23 𝑥x 10-12 JB.1.57 𝑥x 10-3 JC.9.44 𝑥x 1020 JD.3.15 𝑥x 1012 J
Question
What is the binding energy of a nucleus that has a mass defect of 5.81 𝑥x 10-29 kg?A.5.23 𝑥x 10-12 JB.1.57 𝑥x 10-3 JC.9.44 𝑥x 1020 JD.3.15 𝑥x 1012 J
Solution
The binding energy of a nucleus can be calculated using Einstein's mass-energy equivalence principle, which states that E=mc^2, where E is energy, m is mass, and c is the speed of light.
Given: Mass defect (Δm) = 5.81 x 10^-29 kg Speed of light (c) = 3.00 x 10^8 m/s
We can substitute these values into the equation:
E = Δm * c^2 E = 5.81 x 10^-29 kg * (3.00 x 10^8 m/s)^2 E = 5.81 x 10^-29 kg * 9.00 x 10^16 m^2/s^2 E = 5.229 x 10^-12 Joules
So, the binding energy of the nucleus is approximately 5.23 x 10^-12 J. Therefore, the correct answer is A. 5.23 x 10^-12 J.
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