Find the value of base current if the emitter current is 1 milli amps and current amplification factor is 0.9, in a common base transistor configuration a.IC=-0.9 & IB=0.1 milli ampsb.IC=0.1 & IB=0.0milli ampsc.IC=0.9 & IB=-0.1 milli ampsd.IC=0.9 & IB=0.1 milli ampse.None of the above

In a common base transistor configuration, the relationship between the emitter current (IE), base current (IB), and collector current (IC) is given by the equation:

IE = IC + IB

Given that the emitter current (IE) is 1 milliamp (mA) and the current amplification factor (β) is 0.9, we can express the collector current (IC) as a product of the base current (IB) and the current amplification factor (β). Therefore:

IC = β * IB

Substituting the given values into the equation:

1 mA = 0.9 * IB + IB

Solving for IB gives:

IB = 1 mA / (0.9 + 1)

IB = 1 mA / 1.9

IB = 0.526 mA

Therefore, the base current (IB) is approximately 0.526 mA.

Looking at the options provided:

a. IC = -0.9 mA & IB = 0.1 mA b. IC = 0.1 mA & IB = 0.0 mA c. IC = 0.9 mA & IB = -0.1 mA d. IC = 0.9 mA & IB = 0.1 mA e. None of the above

None of the options match the calculated base current (IB) of approximately 0.526 mA. Therefore, the correct answer is:

e. None of the above.