Aptitude:speed and distance [Section 1 of 1] Q7 of 30 Marks 1 General Instructions 100% ×CloseTest time left: 16:38Select the correct answerA cyclist travels a certain distance in 6 hours at a uniform speed. In return, he increases his speed by 2 kmph. and covers the same distance in 5 hours. What was his speed initially?
Question
Aptitude:speed and distance [Section 1 of 1] Q7 of 30 Marks 1 General Instructions 100% ×CloseTest time left: 16:38Select the correct answerA cyclist travels a certain distance in 6 hours at a uniform speed. In return, he increases his speed by 2 kmph. and covers the same distance in 5 hours. What was his speed initially?
Solution
Let's denote the initial speed of the cyclist as x km/h.
According to the problem, the cyclist travels a certain distance in 6 hours at this speed. Therefore, the distance he covers can be represented as 6x.
When returning, the cyclist increases his speed by 2 km/h and covers the same distance in 5 hours. Therefore, the distance can also be represented as 5(x + 2).
Since the distance covered in both cases is the same, we can equate the two expressions and solve for x:
6x = 5(x + 2)
Expanding the right side gives:
6x = 5x + 10
Subtracting 5x from both sides gives:
x = 10
Therefore, the initial speed of the cyclist was 10 km/h.
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