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If a rock falls from a height of 50 meters on Earth, the height H (in meters) after x seconds is approximately H(x) = 50-4.9x^2 When does the rock strike the ground? Round to the nearest hundredth, if necessary.

Question

If a rock falls from a height of 50 meters on Earth, the height H (in meters) after x seconds is approximately H(x) = 50-4.9x^2 When does the rock strike the ground? Round to the nearest hundredth, if necessary.

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Solution

The rock strikes the ground when the height H(x) is equal to 0. So, we need to solve the equation 50 - 4.9x^2 = 0 for x.

Step 1: Rearrange the equation to isolate the term with x^2: 4.9x^2 = 50

Step 2: Divide both sides by 4.9 to solve for x^2: x^2 = 50 / 4.9 x^2 = 10.20408163

Step 3: Take the square root of both sides to solve for x. Since time cannot be negative, we only consider the positive root: x = sqrt(10.20408163) x = 3.19 (rounded to the nearest hundredth)

So, the rock strikes the ground approximately 3.19 seconds after it falls.

This problem has been solved

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