Determine the zeros and y intercept for the rational function: R(x) = (x^3 - 27)/x^2?Question 37Answera.(3, 0); noneb.none; (3, 0)c.none; (0, 3)d.(-3, 0); none
Question
Determine the zeros and y intercept for the rational function: R(x) = (x^3 - 27)/x^2?Question 37Answera.(3, 0); noneb.none; (3, 0)c.none; (0, 3)d.(-3, 0); none
Solution
To find the zeros of the function, we set the numerator equal to zero and solve for x:
x^3 - 27 = 0 x^3 = 27 x = cube root of 27 x = 3
So, the zero of the function is x = 3.
The y-intercept of a function is found by setting x = 0. However, in this case, if we set x = 0, the denominator of the function becomes zero, which is undefined. Therefore, there is no y-intercept for this function.
So, the answer is (3, 0); none.
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3) 27x ^ 3 - 9x ^ 2 - x + 3 = 0 if x = 1/3
To find the intercepts of the function f(x) = (x-3)/(x^2 + 2x -3), we need to find the x-intercept and the y-intercept. 1. X-intercept: The x-intercept is the value of x when f(x) = 0. So, we set the function equal to zero and solve for x. 0 = (x-3)/(x^2 + 2x -3) This implies that the numerator of the fraction must be zero (since zero times anything is zero). So, we set x - 3 = 0 and solve for x. x - 3 = 0 x = 3 So, the x-intercept is 3. 2. Y-intercept: The y-intercept is the value of f(x) when x = 0. So, we substitute x = 0 into the function and solve for f(x). f(0) = (0-3)/(0^2 + 2*0 -3) = -3/-3 = 1 So, the y-intercept is 1. Therefore, the intercepts of the function are x = 3 and y = 1. Context: this is mcq a) (2,0) b) (3,0) C) (1,0)
Find the indicated intercept(s) of the graph of the function. f(x) = (x-3)/(x^2 + 2x -3)
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