Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1."BCl3; + H2O → H3BO3 + HCl

To balance the given reaction: BCl3 + H2O → H3BO3 + HCl

Step 1: Count the number of atoms on each side of the equation. On the left side: 1 B atom, 3 Cl atoms, 2 H atoms, and 1 O atom. On the right side: 1 B atom, 1 Cl atom, 3 H atoms, and 1 O atom.

Step 2: Balance the atoms that are not already balanced. Since the number of B atoms and O atoms are already balanced, we need to balance the Cl and H atoms.

Step 3: Balance the Cl atoms. On the left side, we have 3 Cl atoms, while on the right side, we have only 1 Cl atom. To balance the Cl atoms, we need to put a coefficient of 3 in front of HCl on the right side.

BCl3 + H2O → H3BO3 + 3HCl

Step 4: Balance the H atoms. On the left side, we have 2 H atoms, while on the right side, we have 3 H atoms. To balance the H atoms, we need to put a coefficient of 2 in front of H2O on the left side.

BCl3 + 2H2O → H3BO3 + 3HCl

Step 5: Check if all the atoms are balanced. On the left side: 1 B atom, 3 Cl atoms, 4 H atoms, and 2 O atoms. On the right side: 1 B atom, 3 Cl atoms, 4 H atoms, and 2 O atoms.

All the atoms are now balanced.

The balanced equation is: BCl3 + 2H2O → H3BO3 + 3HCl