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A brown eyed woman (Bb) is having a child with a blue eyed man (bb). All three of their currently born children have blue eyes. What is the chance that their fourth child is born with blue eyes? Question 8Select one: a. 1/4 (0.25). b. 1/2 (0.5). c. 1/8 (0.125). d. 1/16 (0.063). e. 1

Question

A brown eyed woman (Bb) is having a child with a blue eyed man (bb). All three of their currently born children have blue eyes. What is the chance that their fourth child is born with blue eyes?

Question 8Select one:

a. 1/4 (0.25).

b. 1/2 (0.5).

c. 1/8 (0.125).

d. 1/16 (0.063).

e. 1

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Solution

The woman's genotype for eye color is Bb (brown), and the man's genotype is bb (blue). When you create a Punnett square for these genotypes, you get the following possibilities for their children's genotypes: Bb, Bb, bb, bb.

This means that there is a 1/2 (0.5) chance that their child will have blue eyes (bb). So, the correct answer is:

b. 1/2 (0.5).

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