What value does the following code output at line 7? 1 #include <iostream>2 using namespace std;34 int main(){5 int foo = 77;7 cout << &foo << endl;8 return 0;9 } 1 a memory address, such as 0x7fffeb17da34 which may vary each time the program is run none of the other choices No answer text provided. 0 compile error because foo was not initialized 77
Question
What value does the following code output at line 7? 1 #include <iostream>2 using namespace std;34 int main(){5 int foo = 77;7 cout << &foo << endl;8 return 0;9 } 1 a memory address, such as 0x7fffeb17da34 which may vary each time the program is run none of the other choices No answer text provided. 0 compile error because foo was not initialized 77
Solution
The output of the code at line 7 will be a memory address, such as 0x7fffeb17da34. This address may vary each time the program is run. This is because the ampersand (&) before "foo" in the cout statement is a unary operator that returns the memory address of its operand.
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