Two friends, Akash & Beenu had some candies each. One of them had 15 candies more than the other. The candies with Akash were 60% of the total candies with them. How many candies did each have?Choices:- 40, 25 47, 32 45, 30 49, 34
Question
Two friends, Akash & Beenu had some candies each. One of them had 15 candies more than the other. The candies with Akash were 60% of the total candies with them. How many candies did each have?Choices:- 40, 25 47, 32 45, 30 49, 34
Solution
Let's solve this step by step:
Step 1: Let's assume that Beenu has X candies.
Step 2: According to the problem, Akash has X + 15 candies (because one of them had 15 candies more than the other).
Step 3: The total number of candies they both have is X (Beenu's candies) + X + 15 (Akash's candies) = 2X + 15.
Step 4: The problem also states that the candies with Akash were 60% of the total candies with them. So, we can set up the equation: 0.60 * (2X + 15) = X + 15.
Step 5: Solving this equation, we get X = 25.
Step 6: Substituting X = 25 in the equation X + 15, we get the number of candies with Akash = 25 + 15 = 40.
So, Beenu had 25 candies and Akash had 40 candies. Therefore, the correct choice is 40, 25.
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